Given f(x)=4x-3, g(x)=(3/5)x+7, and h(x)=2x^2-7x-5, find the following. find g(-10), h(-1)?

Question

need to find the letter x in the () and use one of these forumla to get the answer is to find the letter by the (x) and the number that were already put like G(-10) then put -10 inside the x to find the answer.

Answer 1

g(-10) = 1

Substitute -10 to the function ,

g = 3/5 x (-10) + 7
= -30/5 + 7
= -6 + 7
g = 1

h (-1) = 4

Substitute (-1) to the function
h = 2x^2 - 7x - 5
= 2 x (-1) (-1) - 7(-1) - 5
= 2 x 1 + 7 - 5
= 2 + 7 - 5
= 9 - 5
h = 4

Remember , the product of 2 negative numbers is positive

Answer 2

g(x) = (3/5).x + 7
g(- 10) = (3/5).(- 10) + 7 = - 6 + 7 = 1

h(x) = 2x² - 7x - 5
h(- 1) = 2.(-1)² + 7 - 5 = 2 + 7 - 5 = 4

Answer 3

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Answer 4

if x=-10 then
g(x=-10)=(3/5)*(-10)+7=+1


then if x=-1 then:
h(x=-1)= 2*(-1)^2-7*(-1)-5=4