Two tour guides are leading six tourists. The guides decide to split up. Each tourist must choose one of the guides, but with the stipulation that each guide must take at least one tourist. How many different groupings of guides and tourists are possible???
Choices...
A)56
B)58
C)60
D)62
E)64
2007-03-17 02:47:56 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
suppose the groups are A and B
A=1 : 6 choices for the loner
A=2 : 15 ways
A=3 @ 20 ways
A=4, B=2: 15 ways
A=5, B=1 : 6 ways
total 62
2007-03-17 02:55:41 · answer #1 · answered by hustolemyname 6 · 1⤊ 0⤋
62
2007-03-17 09:56:33 · answer #2 · answered by Ariel 5 · 0⤊ 0⤋
It is really 62 possibilities.
So it's D
2007-03-17 10:57:30 · answer #3 · answered by Someone 1 · 0⤊ 0⤋
Its d
2007-03-17 11:12:15 · answer #4 · answered by homeskillet 3 · 0⤊ 0⤋
c
2007-03-17 09:53:35 · answer #5 · answered by rosecitylady 5 · 0⤊ 1⤋