The numbers 1 to 8 are placed at the vertices of a cube in such a manner that the sum of the for numbers on each face is the same. What is this common sum??
Choices....
A)14
B)16
C)18
D)20
E)24
2007-03-17 02:39:44 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The sum of all the numbers is 1 + 2 + 3 + ... = 36
If you take a face on one side of the cube, it has 4 of the numbers, and if you take a face on the opposite side, it has to have the other 4 numbers. So each face has to have half the numbers. So each face has to have half the sum of all the numbers which is 36/2 = 18 (Answer C)
2007-03-17 02:51:14 · answer #1 · answered by Anonymous · 1⤊ 0⤋
The answer is A
2 + 3 + 4 + 5 = 14
1 + 2 + 5 + 6 = 14
1 + 2 + 3 + 8 = 14
1 + 3 + 4 + 6 = 14
2007-03-17 10:47:26 · answer #2 · answered by detektibgapo 5 · 0⤊ 1⤋
C
The sum of the numbers 1 - 8 is 36. For each side to have the same sum, that sum has to be right in the middle. 36 / 8 * 4 = 18
2007-03-17 09:45:04 · answer #3 · answered by John S 6 · 1⤊ 0⤋
c) 18
2007-03-17 09:49:19 · answer #4 · answered by MICHAEL L 1 · 0⤊ 0⤋