http://mathworld.wolfram.com/QuadraticEquation.html
http://www.analyzemath.com/Graphing/GraphingQuadraticFunction.html
2007-03-17 01:30:25
·
answer #1
·
answered by 1988_Escort 3
·
0⤊
0⤋
To solve a quadratic equation you can for example use the resolving formula x = (- b + or - sqrt(b^2 - 4ac)/(2a)
for ax^2 +bx + c = 0
The graph of the equation is a parabola which will cut the OX axis in 2 points if the roots are real and different. If the roots are the same ie only for x = 0 then the parabola only touches the origin. If the roots are complex (they appear as a conjugate pair always) then there will be no OX interception by the parabola which means that either the parabola is totally in the upper half-plane or tottaly in the lower half-plane
2007-03-17 08:47:06
·
answer #2
·
answered by physicist 4
·
0⤊
0⤋
see if u have two varialble X and Y then:
solve both the equations separatly and then u will get relationship between x and y in both equations separate: then draw a tabe such as:
X Assume a Value
Y find value of y by that assumed value
like this make teo tables of two diff equations with 3 assumptions in each table,
then plot the points and draw lines, ur graph is done
if u have one Variable X:
same method, find the value of x and plot the point , thats ur graph.
2007-03-17 09:15:31
·
answer #3
·
answered by Anonymous
·
0⤊
0⤋
let the quadratic equation be in the form
ax^2+bx+c=0
let us assume x^2 as y
so the equation is reduced to the form,
ay+bx+c=0
that is bx+ay+c=0-------------1
and you also get another equation,that is
y=x^2-------------------------------2
take different values of x and y in both the equations and plot the points in the graph paper.
for equation one,
you get a straight line because the degree is one
for equation 2
you get a curve beacause the degree is two.
these both intersect at two points which are the solutions.
2007-03-17 08:49:32
·
answer #4
·
answered by satwik 2
·
0⤊
0⤋
Find the value of x and y axis and graph it, where x is the horizontal line and y is the vertical line where 0,0 is their common vertex
2007-03-17 08:40:55
·
answer #5
·
answered by detektibgapo 5
·
0⤊
0⤋