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f(x) =
1
p2
exp−(x − μ)2
22 , x 2 <,−1 < μ < 1,  > 0.

2007-03-17 00:57:47 · 1 answers · asked by Anonymous in Science & Mathematics Mathematics

1 answers

1)ln 1=0
2)ln p^2= 2*ln p ( if p is positive) .In general ln p^2 = 2 ln I p I
3ln( exp(-(x-u)^2 = -(x-u)^2
I don't understand the meaning of the last line

2007-03-17 02:56:18 · answer #1 · answered by santmann2002 7 · 0 0

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