Function F is F:x=3x.Another function g is such that (fg)inverse=3/x-1. find the functions fg and g.?

Answer 1

y=3/(x-1)
xy-y=3
x=(3+y)/y
fg(x)= (3+x)/x
f(x)=3x
f(g(x))=3(g(x))
3(g(x))= (3+x)/x
g(x)=(3+x)/3x