How to solve the following physics problem??

Question

A fire helicopter carries a 620-kg bucket at the end of a cable 20.0m long. As the helicopter flies to a fire at a constant speed of 40m/s, the cable makes an angle of 40 degrees with respect to the vertical. The bucket presents a cross-sectional area of 3.80m sq in a plane perpendicular to the air moving past it. Determine the drag coefficient assuming that the resistive force is proportional to the square of the bucket's speed.

Answer 1

I could not draw a picture for you...Here how to solve this problem. There are three force acting on the bucket. The first one is gravity force, mg, pointing down. The second one is pulling force , T, result from the cable. It "lie" along the cable and have direction upward. And the last one is drag force f. You could imagine the direction of the drag force is against (or opposite) the direction of moving plan.

Let set the coordinate system first. You could choose or pick the coordinate system as you like. I pick x-axis is along the moving direction with positive direction is against the moving direction. y-axis is perpendicular to the x-axis of course, with positive right upward.
Now determine the forces acting on xaxis:
f - Tsin40 = 0
forces acting on y-xias:
T cos40 - mg = 0

Using these two equation to find the drag force f:
We got f = mgsin40\cos40
f = mg tang40

Assume f = k A (I am not really sure)
k is coefficient and A is surface area of the bucket
k = f/A
You just plug the numbers in to get the result. Making sure the unit is matching.

Good luck

Answer 2

First calculate how much force is required to push the bucket to a 40 degree angle. Now the drag force will be;

Fd = k x cross section x velocity^2

k is the drag coefficient and cross section is given. Plug in the force you calculated for the drag and solve for k.