For cost and performance, assuming you're only running one subwoofer, your best bet is a 2-channel amp that can be bridged to around 500 watts into a 4-ohm load. You can find plenty of amps that fit that description and they'll be much cheaper than a typical mono amp that provides 500 watts at 4 ohms. Now, if you have a DUAL VOICE COIL sub with 4-ohm voice coils, all bets are off, because that's not really a 4-ohm sub at all.
As for the idea that a 4-ohm sub somehow isn't as good as a 2-ohm sub, that's ridiculous. 500 watts is 500 watts no matter what kind of load it's being driven into. If you're only using one subwoofer, a 4-ohm load is ideal because you have a much wider range of fairly inexpensive amplifiers that will work very well with it.
2007-03-14 01:53:12
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answer #1
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answered by KaeZoo 7
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first of all the stig is wrong. theres no sound difference or quality difference between 2 and 4 ohm subs. its just the measure of the resistance. all u need to do is find an amp with 500 watts rms at 4 ohms. however u might want an amp that runs about 600 watts to get mroe out of ur sub. just dont go over the peak power.
2007-03-14 10:21:39
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answer #2
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answered by harley 3
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a mono amp (1 channel) that is rated for 500 watts rms at 4 ohms.go to onlinecarstereo.com for an amp get 1 that has a high s/n ratio (> 95db )and a bass boost that is atleast +12db and maybe a remote sub gain and you will be happy !!!
2007-03-14 04:08:46
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answer #3
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answered by bigsportsnut2 5
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a 500 rms amp
2007-03-14 03:59:15
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answer #4
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answered by Anonymous
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an amp that puts out pretty much the same.
But really, you need to know how much your sub takes at 2 ohms. 4 ohms sucks, you don't want to run at 4 ohms. Trust me, you want to run at 2 ohms.
Most amps list it's RMS is 2 ohms, so you should know.
If your sub ONLY does 4 ohms you need a new sub.
TS
2007-03-14 04:00:18
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answer #5
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answered by The Stig 3
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Be sure the amp you get is CEA-2006 compliant. KaeZoo is totally right.
See my site for more info http://spkrbox1.spaces.live.com
2007-03-14 11:45:50
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answer #6
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answered by Anonymous
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