Can I tie the input and the clock of a D-latch together?

Question

I need a simple latch that can accept a momentary high signal and send a high output until a reset signal turns the output low. I am thinking that I can just tie together the clock and the input together on a positive edge D-latch to accomplish this. However, I also know that it all assumes the fact that the input and the clock will be seeing a high signal at exactly the same. Will this work or so I need to try something else?

It is basically a switch that can be turned on by turning on input high and off by turning another input high. I don't want to use a T flip flop because it only gives me one input.

Answer 1

Its simple really.. u mentioned that one input turns output on and the other turns it off.. If this is the case, u just need to delay one of the inputs by a tiny bit.. to this just connect two not gates (or a single buffer) to get the delay.. Every gate has something called a propogation delay.. its the time taken for signal to go from input to output.. it is usually in nanoseconds.. U jest need to put the right number of gates to delay one signal by a certain period of time..

Answer 2

It might work, but if I were using a D latch, I'd just tie the input high and run the sensor signal into the clock. Even this may be overkill; a latch consisting of cross-connected NAND gates would be adequate for what you are trying to do.

Answer 3

No, it won't work. If you need an edge to turn it on and the next edge to turn it off, tie the D input to the ~Q output. Then it will toggle nicely.

HTH ☺

Doug

Answer 4

so basically u want a toggle switch? like a
T flip-flop