Tough math one?

Question

A small zoo had just mammals and birds. When asked how many of each they had, the zoo keeper said he had a total of 54 animals with a 140 feet total between them all. Assuming all the animals had all the feet they should have, how many birds and how many mammals were there?

Not that there are many, but.

Possibly the only mammals other than humans that commonly move bipedally by an alternating gait rather than hopping are gibbons when on the ground, and giant pangolins.

So, go with the four legged ones. Thank you! Hoppers don't count either.

Answer 1

38 birds , 16 mammals

Answer 2

38 birds 38 x 2 = 76
16 mammals 16 x 4 = 64
54

76+ 64 = 140

Answer 3

Assuming every mammal has 4 legs and every bird has 2; there are 16 mammals and 38 birds in the zoo.

Answer 4

This is a trick question. Everyone is saying 16 mammals and 38 birds, but there Could be 18 mammals and 36 birds.

Answer 5

There are 16 mammals (4 legged varieties) and 38 birds (2 legged varieties) total 54 animals

Answer 6

Need to know what types of animals....some mammals walk on 4 legs and some walk on 2.....

Assuming they walk on all 4 you would have 16 mammals (64 feet) and 38 birds (76 feet)

16+38= 54

64+76= 140

Answer 7

16 birds 38 mammals

Answer 8

this can be easily solved by algebra
suppose a is no. of mammels and b is birds
so a+b=54
a=54 -b
&
4*a+2*b=140
substituting the value of a
4*[54 - b]+2b= 140
216 -4b +2b =140
-4b +2b = -216+140
-2b = -76
b = 38
a 54-38= 16
so there are 16 mammels and 38 birds
b=76/4 =19
there are 19 birds and 35 mammels

Answer 9

That depends on whether the mammals are bipedal or quadripeds.

Answer 10

280