Do you think it's possible to build an "integrator", differentiator", "phase shifter" or a "filter" by using RL circuit? Explain you answer please.. thanks.. I don't have a clue about this.. I'm doing my lab report... T.T
2007-03-10 10:05:49 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
If L is inductance and R is resistance then:
V = Ldi/dt +Ri, where V is voltage and i is the current.
Voltage can be an alternating source represented by:
Vsin(2pi ft), where f is frequency and t is time.
Use the resulting differential equation to see what results are possible.
2007-03-10 10:21:03 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
Is the RL circuit sequence or parallel? Assuming sequence, yet please state one or the different. Saturated or unsaturated, the present is desperate by ability of the inductance and the resistance, and that's certainly a ramp changing to a horizontal line by way of fact the present strategies the linked fee desperate by ability of the resistance, I = E/R. If the inductor saturates (and there is not any requirement that it do) then this is inductance drops and the slope of the curve could enhance, except the resistor compensates for that. pass by ability of the equations.
2016-12-14 15:49:20 · answer #2 · answered by ? 4 · 0⤊ 0⤋
You can build as integrator and filter(low pass)
2007-03-10 11:46:19 · answer #3 · answered by JAMES 4 · 0⤊ 0⤋
Hhmmm.....Yes.....but you need a capacitance
2007-03-10 13:16:20 · answer #4 · answered by reden 2 · 0⤊ 0⤋