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each side of the pentakaidecagon is 10 feet tall; creating a structure with an inside measurement of 900 sqft. How long would each side be? I am using 8"x8"x16" concrete blocks
to build this structure.

2007-03-10 05:32:41 · 2 answers · asked by thedude50 1 in Science & Mathematics Engineering

2 answers

A = n(s/2)^2/tan(180/n)
s = 2√(A/n)tan(180/n)
s = 2√(900/15)tan(180/15)
s = 60√(1/15)tan(180/15)
s = 7.1424 ft = 7 ft 1.7085 in = 5.3568 blocks, or about 5 3/8 blocks

2007-03-10 06:35:36 · answer #1 · answered by Helmut 7 · 0 0

First of all you spelled it wrong it's Pentadecagon.Second look it up on the computerat

http://mathworld.wolframe.com/Pentadecagon.html.

Hope it helps.

2007-03-18 13:41:11 · answer #2 · answered by Sam 2 · 0 0

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