A crate is pulled 3.0 m at constant velocity along a 30 degreeincline. The coefficient of kinetic friction between the crate and the plane is 0.20. Calculate the efficiency of this procedure
2007-03-09 23:53:46 · 4 answers · asked by Amiraan 4 in Science & Mathematics ➔ Physics
oK, let's start like this, if it's traveling at a constant speed, there is no acceleration.
Friction Force = Normal*u
u : coefficient of kinetic friction
Friction Force = mg*cos(30)*0.2 = mg*sqrt(3) Newtons
So, the work done by the force of friction will be :
W = mg*sqrt(3)*3 = 3mg*sqrt(3)
That's what you can calculate, hope that helped you.
2007-03-10 01:57:13 · answer #1 · answered by anakin_louix 6 · 1⤊ 0⤋
Don't you need to know the weight of the crate to accurately calculate the efficiency? Also, is it being pulled manually or by machine? A person will grow increasingly more tired as the crate is pulled further up the incline.
2007-03-10 00:05:17 · answer #2 · answered by Steve T. 3 · 0⤊ 1⤋
depends upon whos pulling the crate........LOL
2007-03-09 23:59:58 · answer #3 · answered by shahidandasma 1 · 0⤊ 1⤋
Yes I'm sure there's at least one person on this sight that can answer your question.
2007-03-10 00:00:58 · answer #4 · answered by Anonymous · 0⤊ 2⤋