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chemical bonding

2007-03-09 23:26:57 · 12 answers · asked by jkool 1 in Science & Mathematics Chemistry

12 answers

oxygen atom in water molecule has two lone pairs; due to small size of oxy , the lone pair-lone pair and the bond-pair bond-pair repulsion is large and as a result tend to push the molecule apart ; however in H2S, the sulphur atom is greater in size and the lone pair tend to be far apart, thereby considerably reducing the repulsions and also the bond angle. that is the reason.

2007-03-09 23:41:52 · answer #1 · answered by hariharan_hn 2 · 6 1

Bond Angle Of H2o

2016-12-17 15:20:06 · answer #2 · answered by ? 4 · 0 0

H2o Bond Angle

2016-10-04 03:05:27 · answer #3 · answered by ? 4 · 0 0

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RE:
why is the bond angle of H2S smaller than H2O?
chemical bonding

2015-08-10 22:53:44 · answer #4 · answered by Delfina 1 · 0 2

The bond angle is dependent on the energy orbitals at which the bonding between the two occurs also associated with the same is the spin states and whether it is a half filled or fully filled orbital after bonding.
The difference of these characteristics between Sulphur atonm and an Oxygen atom is the key to the length of bond angle.

2007-03-09 23:37:09 · answer #5 · answered by sudiptocool 2 · 0 1

The bond angle is dependent on the energy orbitals at which the bonding between the two occurs also associated with the same is the spin states and whether it is a half filled or fully filled orbital after bonding.
The difference of these characteristics between Sulphur atonm and an Oxygen atom is the key to the length of bond angle

2007-03-10 14:43:54 · answer #6 · answered by kartik 2 · 0 2

H-S-H & H-O-H

The only primary difference between these two molecules is the central atom. Both S and O are p-block elements i.e. the valence electrons of these atoms are present in p-block only.

Atomic number :

S - 16

O - 8

The number of non - valence electrons in S is greater than that in O. Therefore, the free electrons are greater in the negative charge for S than O. The free electron pairs for S is greater in number than O. Therefore, these electron pairs repel the positive charges of H^+ ions of hydrogen atoms. Thus, the bond angle on the other side is shrunken in the case of H2S more than that of H2O.

2007-03-10 00:43:27 · answer #7 · answered by Anonymous · 0 2

Perhaps sulfur s atomic orbitals do not hybridize. If the bonding orbitals remain as a 3px and a 3py, then the expected bond angles would be 90 degrees.

2016-03-18 07:28:00 · answer #8 · answered by ? 4 · 0 0

My guess is because Oxygen is more electronegative than sulfur. (Linus Pauling's concept of electronegativity) Thus pulling the Hydrogen atoms closer.
The bond angle for H20 is 105 degrees.

Remember also the concept of Hydrogen bonding. This concept helps explain how multiple molecules/formula units
of water will align themselves. With Hydrogen atoms from other molecules being attracted to the back side of an oxygen atom in another molecule.

2007-03-10 00:05:49 · answer #9 · answered by MARK 2 · 0 2

The hydrogens show a fictive charge positive one each of them so they repel each over.

For H2S the bound H-S is less polar than H-O , so the repulsion is smaller and the angles between the two bounds S-H smaller

2007-03-10 00:41:28 · answer #10 · answered by maussy 7 · 0 2

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