probability ?

Question

all 3 face cards of spades are removed from a pack of 52 cards. what is the probability of getting
1.black card -
2.queen
3. black face card

Answer 1

Are you talking about after shuffling and dealing one card?

If you shuffle each time and then deal one card each time, then the odds are completely different than going through the whole deck at one time.

You will have 23 black cards out of 49 remaining

You will have 3 queens remaining out of 49 cards

and you will have 3 black face cards remaining out of 49 cards

to get your answer reshuffling each time

black card- 23 in 49 to the 49th power

queen and black face card- 3 in 49 to the 49th power

hope that helps

Answer 2

Already everyone has answered the question correctly. Since you have extended the expiration date, I can supply some more information.
If these cards are removed without replacement then above case presents three possibilities:
(a)black non-face card, queen and a black face card(club king and jack)
(b)black face card(club king/ jack--without queen), queen(heart, club and diamond),black face card(club jack/king)
(c)black queen(club queen), queen(heart and diamond), black face card(club king and Jack)
3 cards out of 49 could be selected in (49 choose 3)=18424 ways. n(S)=18424

(A)Let E' be the event described in (a)
n(E')=(20 choose 1)x(3 choose 1)x(2 choose 1)
n(E')=120 ways
P(E')=120/18424

(B) Let E'' be the event described in (b)
n(E'')=(2 choose 1)x(3 choose 1)
n(E'')=6 ways
P(E")=6/18424

(C)Let E'''be the event described in (c)
n(E''')=(1 choose 1)x(2 choose 1)x(2 choose 1)
n(E''')=4 ways
P(E''')=4/18424
Required event E=E' U E'' U E'''
P(E)=P(E')+P(E'')+P(E''')
= (120 + 6 +4) / 18424
=130/18424

Answer 3

there are 13 cards of each type

after removing the 3 face cards(Jack, Queen, King)

u will have 10 spades and 49 cards

so P(black card) = ( 10 + 13)/ 49
= 23/49
there are 3 queens left

so P(queen) = 3/49

as for the third , sorry but i do not understand wat is meant by a black face card

Answer 4

1. 26/49
2. 4/49
3. 3/49 (as only the 3 face cards of clubs will remain)

Answer 5

P(E)=no. of favourable outcomes/total no. of outcomes

Total outcomes=52-3=49

1. P(black card)=23/49
2. P(queen)=3/49
3. P(black face card)=3/49

well, r u givin da Xth boardz????

Answer 6

1. 23/49
2. 3/49
3. 3/49 (as only the 3 face cards of clubs will remain)

Answer 7

1. one in 23
2. three in 49
3. three in 49