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for example a person jumping out of a plane without parachute from 32000 feet high ... by the time he hits the ocean surface he would have reached really great speeds??? will the water give in or will it just act as a solid at the moment of impact?

2007-03-09 20:42:02 · 6 answers · asked by chan 1 in Science & Mathematics Physics

6 answers

will act as liquid for the case specified. however when the angle of impact changes then water can deflect(bullets)

2007-03-09 20:52:02 · answer #1 · answered by purimani2005 4 · 0 0

It depends how the person makes contact with the water. For eg: if the person makes a contact vertically so at the point of contact his surface area will be too less and hence water will act like a fluid to him. But if he makes a contact with the water surface horizontally his surface area will be more and hence the water will act as a solid surface. But if he makes an inclined contact then it might happen that the person makes one or two bounce before drowning.

2007-03-09 22:05:43 · answer #2 · answered by Napster 2 · 0 0

I may not be answering your actual question, but the surface tension of calm water is sufficient that he/she will feel the same as if he/she were hitting a solid surface such as rock. If the water is not calm, the impulse from hitting the ocean will be less, though probably enough to kill someone from 32000 feet.

2007-03-09 22:10:04 · answer #3 · answered by racecar0 1 · 0 0

Liquids impacted by objects moving at high velocities behave quite strangely. The water would still be acting as a liquid but to the poor person falling at that speed it would feel like hard rock. Nor do you need that much altitude. Bridge jumpers usually die of concussion or broken neck, not drowning.

2007-03-09 21:01:20 · answer #4 · answered by Helmut 7 · 0 0

Ignoring, for the sake of argument, the impossibility of this type of bullet, why could the glass no longer shatter? the only threat could be interior the technical distinction between shattering, or the bullet passing by, fusing the sides of the hollow left at the back of by way of great warmth generated by ability of the friction of the bullet pasing the glass. nonetheless, how does a bullet stay on the warmth of such friction? No, the bullet, glass and each little thing for thousands of ft around could be destroyed by ability of the ask your self wave of the passing bullet. (which does no longer proceed to exist this is very own ask your self wave, so, would not attain the glass, interior the 1st place.) Which brings us back to the question of the gun. Ouch. Now, evaluate relativity, itself. The bullet, AND the glass must be mentioned to be drawing close one yet another on the fee of sunshine. Which shatters which?

2016-12-14 15:24:54 · answer #5 · answered by Anonymous · 0 0

It will act very much like a solid upon impact.

2007-03-09 20:52:01 · answer #6 · answered by daddyspanksalot 5 · 0 0

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