1*10^42=(0.16)/(x)(2.0)^6
2007-03-09 18:45:19 · 8 answers · asked by FaceFullofFashion 6 in Science & Mathematics ➔ Mathematics
well that was easy lol, ty
2007-03-09 19:10:04 · update #1
=16/(10^42 * 2^4 * 4 *10^2)
=1/4*10^44
=25*10^(-46)
2007-03-09 18:53:52 · answer #1 · answered by SS 2 · 0⤊ 0⤋
To solve for X one must first isolate X to one side of an equation
1*10^42=(0.16)/(x)(2.0)^6
(1*10^42)(1/0.16)=[(0.16)/(x)(2.0)^6](1/(0.16)
1*10^42/0.16=(x)(2.0)^6
(1*10^42/0.16)(1/(2.0)^6)((x)(2.0)^6)
(1*10^42)/((2.0)^6)(0.16)=x
x=1*10^42/0.32^6
2007-03-09 19:11:28 · answer #2 · answered by ot43isme 1 · 0⤊ 0⤋
10 ^ (42) = (0.16) / (2 ^ (6) . X)
X = ( 0.16) / [10 ^ (42) x 2 ^ (6)]
X = 2.5 x10 ^ (-3) x 10 ^ (- 42)
X = 2.5 x 10 ^ (- 45)
2007-03-09 22:25:59 · answer #3 · answered by Como 7 · 0⤊ 0⤋
1* 10^42 = 0.16/ x * 2^6
or 10 ^42 = 0.16/64x
or x = 0.16 / 64 * 10 ^42
or x = 0.25 * 10^ -44
2007-03-09 18:56:12 · answer #4 · answered by ritesh s 2 · 0⤊ 0⤋
x= 0.16/(10^42 * 2^6)
2007-03-09 18:49:12 · answer #5 · answered by slovakmath 3 · 0⤊ 1⤋
1*10^42=(0.16)/(x)(2.0)^6
1*10^42=(0.16)/(x)(64)
1*10^42=1/400x
400x =10^-42
x = (1/400)*10^-42
x =(0.0025)*10^-42
x =2.5 *10^-45
2007-03-09 19:09:52 · answer #6 · answered by PC_Load_Letter 4 · 0⤊ 0⤋
Simplify it first then solve for X
2007-03-09 18:48:38 · answer #7 · answered by exo 7 · 0⤊ 1⤋
2.5E-45
2007-03-09 19:05:54 · answer #8 · answered by bearmuscle13 1 · 1⤊ 1⤋