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6z^7 - 10z^6 - 24z^5

2007-03-09 16:04:07 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

6z^7 - 10z^6 - 24z^5
= 2z^5 (3z² - 5z - 12)
= 2z^5 (3z+4) (z-3)

2007-03-09 16:07:01 · answer #1 · answered by smci 7 · 0 0

6z^7 - 10z^6 - 24z^5

2z^5(3z^2 - 5z - 12) {remove common factor}

2z^5(3z + 4)(z - 3) {factor the trinomial}

See the lesson at the link below

2007-03-10 00:11:35 · answer #2 · answered by kindricko 7 · 0 0

6z^7 - 10z^6 - 24z^5
Highest common factor is 2z^5. Factor it out

6z^7 - 10z^6 - 24z^5
= 2z^5(3z^2 - 5z - 12)
= 2z^5(3z^2 - 9z + 4z - 12)
= 2z^5[3z(z - 3) + 4(z - 3)]
= 2z^5(z - 3)(3z + 4)
= 2(z^5)(z-3)(3z+4)

2007-03-10 00:34:27 · answer #3 · answered by Akilesh - Internet Undertaker 7 · 0 0

6z^7 - 10z^6 - 24z^5
= 2(3z^7 - 5z^6 - 12z^5)
= 2(z^5)(3z^2 - 5z - 12)
= 2(z^5)(3z + 4)(z - 3)

2007-03-10 00:11:02 · answer #4 · answered by Adrianne G. 2 · 0 0

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