A 1.00 kg block of ice at 0 degree Celsius is added to a picnic cooler.How much heat will the ice remove as it

Question

melts to water at 0 degree Celsius?

Answer 1

The latent heat of fusion for ice is 332000 J/Kg
Q=Lv*m
=(332000)*(1)
Q=332000 J
1 cal=4.168 J
332000/4.168= 79.7 kcal
It will remove or absorb 332000 J or roughly 79.7 kcal of heat.

Answer 2

Heat of fusion for water = 79.72 calories/gram

heat =( 79.72 calories / gram ) * 1000 grams =
7972 calories = 79.72 kcal