A 60 kg person will need to climb a 10 m stairway how many times to "work off" each excess Cal(kcal) consumed?

Answer 1

Convert cal. into J. using Joule's Law, I suppose 1J = 4.18 cal. So 1cal = 1/4.18 J Then divide by mgh = 60*9.81*10 J u will get the no. of times he has to climb up. But any how the person cannot climb up without coming down, when he comes down his potential energy is restored and he would have done work onty due to friction.

Answer 2

W=FD

F=9.8(60)=588N
D=10m
W=588*10=5880J
1kcal=4186J
5880/4186=1.4

For each excess kcal consumed the person has to climb 1.4- 10m staircases

Answer 3

E=mgh=60*9.8*10
=6000 ( J)