Machinists at the space port's machine shop have fabricated a pipe that is 8m long and 3cm in diameter...?

Question

Machinists at the space port's machine shop have fabricated a pipe that is 8m long and 3cm in diameter. They must transport it down a corridor 3m wide by 3m high that has a right-angled corner. The pipe must not be bent or twisted. Will it fit around the corner? What is the longest pipe that will fit around the corner?

Can you show me how you got it? Thanks.

Answer 1

if you have a right angle corner of a three meter wide and three meter high corridor, the widest part is fro top side of the outside edge of on corridor to the bottom corner of the of the intersecting corner. If the intersection is 90 degrees then the m the widest point is three meters behind the inside corner of the intersection making that side of your triangle 6 meters, since the other side will be the same, your triangle is 6m x 6m now you need to find the measurement of the base so in a right angle triangle yo do this by A squared +B squared + C Squared, you know A and you know B so your base dimension works out to 6.4801 meters...not enough room, however, you can go from ceiling to floor , and you figure this out because you have a rectangle of the original base dimension x the height of the corridor 3M x 6.4801 M again Pythagoras theorem gives you 9 +41.99 = 50.99 the square route of which is7.14M your answer is NO it will not go around the corner, the longest pipe you will ge around that corner without bending or twisting is 7.08M (you loose 3 CM on each end because the pipe is round and will not fit tightly into the corner which is the maximum dimension.