Fluorine reacts with oxygen to yield oxygen difluoride 2 F2(g) + O2(g) = 2OF2(g)?

Question

What is the value of K if the following concentrations are found at equilibrium? [O2] = 0.200 mol / L, [F2] = 0.0100 mol / L, OF2] = 0.0633 mol / L

I need help, I am just lost on this one.

Answer 1

Kc=[OF2]^2*/([F2]^2*[O2])
Kc=(.0633)^2/(.0100^2)(.200)
Kc=200.34
or Kc= .2*10^3
good luck

Answer 2

according to the law of mass action,
k= [of2]^2/[o2][f2]^2


k=0.0633*0.0633/0.200*0.0100*0.0100

k=0.00400689/0.00002 =200.3445