sulfur, S8
methane, Ch4
carbon monoxide,CO
cobalt, CO
2007-03-09 08:22:59 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
The element, compound, compound, element answers are correct. However Cobalt should be written as Co. CO is the formula for carbon monoxide which has one atom of Carbon(C) and one atom of oxygen (O). Cobalt is an element whose symbol is Co.
2007-03-09 08:30:44 · answer #1 · answered by hcbiochem 7 · 2⤊ 0⤋
Look at your formulas. If there is more that one element in it, then it is a compound.
Ex. S8- 8 sulfur atoms. More than 1 atom, but only ONE element, therefore, S8 is just an element.
Also, be sure that you are correctly copying the formulas and abbreviations. CO is carbon monoxide; Co is cobalt.
2007-03-09 08:30:50 · answer #2 · answered by kdd_angel 3 · 1⤊ 0⤋
Hi. An element only has one material. A compound two or more. You have CO in back of carbon monoxide (One C and one O) and also behind cobalt, but THAT CO is the abbreviation for cobalt.
2007-03-09 08:27:22 · answer #3 · answered by Cirric 7 · 1⤊ 0⤋
Look at them! Sulphur and cobalt can be found on the Periodic Table of the Elements. Methane and Carbon Monoxide contain COMPOUNDS of carbon, hydrogen, and oxygen. Why do you need help with something so simple?
2007-03-09 08:35:36 · answer #4 · answered by Anonymous · 0⤊ 1⤋
sulfur and cobalt are elements , methane and carbon monoxide are compounds
2007-03-09 09:34:54 · answer #5 · answered by Chess 2 · 0⤊ 0⤋
Sulfur and cobalt are elements. The others are compounds.
2007-03-09 08:36:20 · answer #6 · answered by Anonymous · 0⤊ 0⤋
sulfur -compound,methane- element, carbon monoxide (mono-one)element,not too sure about cobalt
2007-03-12 04:42:29 · answer #7 · answered by Hells Bells 2 · 0⤊ 0⤋
Element
compound
compound
element
2007-03-09 08:28:56 · answer #8 · answered by Anonymous · 2⤊ 1⤋
Haven't thought too much about this
2016-09-19 14:49:06 · answer #9 · answered by Anonymous · 0⤊ 0⤋
I also have the same question
2016-08-14 08:47:28 · answer #10 · answered by Anonymous · 0⤊ 0⤋