cans someone help me provide the equations for the following asap?

Question

CuCo3(s)+HCl(aq) ,
Cuo(s)+HCl(aq),

AgNO3(aq)+HCl(aq),
Pb(NO3)2(aq)+HCl(aq),
Cu(NO3)2(aq)+HCl(aq),
F(eNO3)2(aq)+HCl(aq),
Ba(NO3)2(aq)+HCl(aq),
KNO3(aq)+HCl(aq),

AgNO3(aq)+NaOH(aq),
Pb(NO3)(aq)+NaOH(aq),
Cu(NO3)2(aq)+NaOH(aq),
Fe(NO3)3(aq)+NaOH(aq),
Ba(NO3)(aq)+NaOH(aq),
KNO3(aq)+NaOH(aq),

AgNO3(aq)+H2SO4(aq),
Pb(NO3)2(aq)+H2SO4(aq),
Cu(NO3)2(aq)+H2SO4(aq),
Fe(NO3)3(aq)+H2SO4(aq),
Ba(NO3)2(aq)+H2SO4(aq),
KNO3(aq)+H2SO4(aq),

Answer 1

CuCO3(s)+ 2HCl(aq) -----> CuCl2(aq) + H2O(l) + CO2(g)
CuO(s)+ 2HCl(aq) -----> CuCl2(aq) + H2O(l)

AgNO3(aq)+HCl(aq) -----> AgCl(s) + HNO3 (aq)
Pb(NO3)2(aq)+ 2HCl(aq) -----> PbCl2(s) + 2HNO3 (aq)
Cu(NO3)2(aq)+ 2HCl(aq) -----> CuCl2(aq) + 2HNO3 (aq)
Fe(NO3)2(aq)+ 2HCl(aq) -----> FeCl2(aq) + 2HNO3 (aq)
Ba(NO3)2(aq)+ 2HCl(aq) -----> BaCl2(s) + 2HNO3 (aq)
KNO3(aq)+ HCl(aq), -----> KCl(aq) + HNO3 (aq)

AgNO3(aq)+NaOH(aq) -------> AgOH (aq) + NaNO3(aq)
Pb(NO3)2(aq)+ 2NaOH(aq) -------> Pb(OH)2(s)+ 2NaNO3(aq)
Cu(NO3)2(aq)+ 2NaOH(aq) -------> Cu(OH)2(s)+ 2NaNO3(aq)

Fe(NO3)3(aq)+ 3NaOH(aq) -------> Fe(OH)3(s)+ 3NaNO3(aq)

Ba(NO3)2(aq)+NaOH(aq) -------> Ba(OH)2(s)+ 2NaNO3(aq)

KNO3(aq)+NaOH(aq) ---------> KOH(aq)+ NaNO3(aq)

2AgNO3(aq)+ H2SO4(aq)--------> Ag2SO4 (s) + 2HNO3 (aq)
Pb(NO3)2(aq)+ H2SO4(aq)---------> PbSO4 (s) + 2HNO3 (aq)
Cu(NO3)2(aq)+H2SO4(aq) --------> CuSO4 (aq) + 2HNO3 (aq)

2 Fe(NO3)3(aq)+ 3H2SO4(aq) --------> Fe2(SO4)3 (aq) + 6HNO3 (aq)

Ba(NO3)2(aq)+H2SO4(aq) --------> BaSO4 (s) + 2HNO3 (aq)

2KNO3(aq)+H2SO4(aq) --------> K2SO4 (aq) + 2HNO3 (aq)

Answer 2

Eeeek! That's waaaaay too many to expect someone to help you with on here dude. If you have that many equations to do surely you have a textbook or class notes too?

Seperate the compounds into their ions eg, Pb2+, NO3-, Na+, H+ etc and rearrange them to react with eachother. Check out the solubility of compounds so you know if any of the equations form a precipitate (that is if one of the compunds is a solid) you also have to make sure the charge is equal on both sides.

e.g.Ba(NO3)2(aq) + H2SO4(aq) --> BaSO4 (s) + 2HNO3(aq)

Some equations will need the number of atoms balanced and stictly speaking you should remove spectator ions (the H+ and NO3- ions in the above equation) as well.

If you're totally desperate try looking up each equation seperately in the search for answers box. I think you'd save yourself some time by opening a book though!

Looking at the answer beneath you're lucky somebody likes doing equations and has the time to do them all for you,but if you ever get tested you'll need to be able to do it yourself!

Answer 3

Wheeeeeee! Homework-Fest!

Answer 4

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RE:
cans someone help me provide the equations for the following asap?
CuCo3(s)+HCl(aq) ,
Cuo(s)+HCl(aq),

AgNO3(aq)+HCl(aq),
Pb(NO3)2(aq)+HCl(aq),
Cu(NO3)2(aq)+HCl(aq),
F(eNO3)2(aq)+HCl(aq),
Ba(NO3)2(aq)+HCl(aq),
KNO3(aq)+HCl(aq),

AgNO3(aq)+NaOH(aq),
Pb(NO3)(aq)+NaOH(aq),
Cu(NO3)2(aq)+NaOH(aq),
Fe(NO3)3(aq)+NaOH(aq),
Ba(NO3)(aq)+NaOH(aq), ...

Answer 5

Ummm no,thats too hard for me i barely know algebra