A spring with a spring constant of 8.0 N/m is compressed by 20 cm. If the spring is uncompressed initially, then the work done is??
how would you do this prob?? please help, thanks
2007-03-09 05:49:14 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The applicable formula for this problem is,
Work = ½ k * x^2
Where k is the spring constant and x is the distance the spring is compressed.
In the problem you are given the spring constant (k = 8.0 N/m) and you are given the distance the spring is compressed (x = 20 cm = .2 meters).
All you need to do is plug into the above formula,
Work = ½ (8.0 N/m) * (.2 meters)^2
Work = .16 Joules
http://cnx.org/content/m14102/latest/
2007-03-09 05:56:44 · answer #1 · answered by mrjeffy321 7 · 0⤊ 1⤋
f=kx
dw=fdx
dw=kx*dx
after integration
w=1/2kx^2
w=8*2/100
w=0.16 J
2007-03-09 13:55:10 · answer #2 · answered by miinii 3 · 0⤊ 0⤋