What is [ OH - ] for a solution where pH = 5.80?

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What is [ OH - ] for a solution where pH = 5.80?

2007-03-09 05:47:17 · 2 answers · asked by simonkf2002 1 in Science & Mathematics ➔ Chemistry

2 answers

if pH = 5.80, then pOH = 14 - 5.8 = 8.2

pOH = -log[OH-] = 8.2

so [OH-] = 10^(-8.2) = 6.31x10^-9 moles/liter

2007-03-09 07:42:28 · answer #1 · answered by Dave_Stark 7 · 0⤊ 0⤋

60.1 x 10^ -9

Then you can find the [OH-] from the pOH
First you find the pOH
pOH + pH = 14
so pOH = 14-pH
pOH= 14- 5.08
pOH = 8.2

[OH-] = 10^-pOH
[OH-]= 10^(- 8.2)
[OH-]= 6.3*10^-9

2007-03-09 14:02:06 · answer #2 · answered by goldengirl 4 · 0⤊ 0⤋