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Calculate [ OH - ] of a 0.210 M solution of Aniline C6H5NH2 Kb = 7.40e-10?

2007-03-09 04:04:19 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

2 answers

C6H5NH2(aq)+H2O(l)-->
C6H5NH3+(aq)+OH-(aq)

equal:


X-2/.210= 7.40e-10


solve for X

X= 1.25e-5

2007-03-09 07:56:09 · answer #1 · answered by bige1236 4 · 0⤊ 0⤋

[OH-] = root (Kb x 0.210).

2007-03-09 12:45:26 · answer #2 · answered by Gervald F 7 · 0⤊ 0⤋

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