I basically have no idea what I'm doing nor know how to go about solving this problem. Does any know how, and if so please explain it to me. Thanks.
2007-03-09 03:34:31 · 8 answers · asked by Twi-Kun 1 in Science & Mathematics ➔ Mathematics
2/(8+x)
2007-03-09 04:21:15 · answer #1 · answered by Alias 2 · 0⤊ 0⤋
f(x)=2 In (8+x)
8+2=10
2007-03-09 11:42:47 · answer #2 · answered by Xiomy 6 · 0⤊ 1⤋
f(x) = 2 ln(8 + x)
Before you start anything, you need knowledge of differentiation, along with the various rules that go along with it. In this case, you need knowledge of the chain rule, and the fact that differentiating a constant times a function is the same as multiplying that constant with the function's derivative.
You also need to know the derivative of g(x) = ln(x). It is
g'(x) = 1/x.
With that said,
f'(x) = 2 [1/(8 + x)] (1)
f'(x) = 2/(8 + x)
2007-03-09 11:39:26 · answer #3 · answered by Puggy 7 · 0⤊ 0⤋
f'(x) = 2/(8 + x)
2007-03-09 11:50:08 · answer #4 · answered by PH 2 · 0⤊ 0⤋
Let y = 2.ln(8 + x) and u = 8 + x
y = 2.ln u and du/dx = 1
dy / du = 2 / u
dy /dx = (dy / du).(du/dx)
dy / dx = (2 / u).(1)
dy / dx = 2 / (8 + x) = f `(x)
2007-03-09 11:53:38 · answer #5 · answered by Como 7 · 0⤊ 0⤋
f'(x) = 2 /(8=x)
If f(x) = ln (x) then f'(x) = 1/x.
Also if f(x) = ln(g(x)) then f'(x) = g'(x)/g(x)/.
2007-03-09 11:40:52 · answer #6 · answered by le_papillon_vert 2 · 0⤊ 0⤋
f'(x)=2*d/dx(ln(8+x))
=2*(1/(8+x)*d/dx(8+x))
=2/(8+x)
2007-03-09 13:10:45 · answer #7 · answered by prince 2 · 0⤊ 0⤋
(x) must be an empty group
2007-03-09 11:44:05 · answer #8 · answered by Yagami 6 · 0⤊ 0⤋