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2007-03-09 03:14:16 · 3 answers · asked by biggurl 1 in Science & Mathematics Mathematics

3 answers

Is the problem to calculate the 21st derivative of xsin(x) at 0? Since x sinx is an even function it will be zero.

2007-03-09 09:47:17 · answer #1 · answered by Sean H 5 · 0 0

Your Teacher loves you, doesn't he (or she)?
Remember
f(x) = g(x)*h(x)
f'(x) = g(x)*h'(x) + g'(x)*h(x)
Now..... Do that 20 more times to get the 21'st derivative ☺

Yeah, it's a sh|tload and a half of terms, but it really isn't as bad as it seems at first glance since all of the terms will involve x, sin(x), or cos(x) and
d/dx x = 1
d/dx sin(x) = cos(x)
d/dx cos(x) = -sin(x)

And it will develop 'character' ☺

Doug

2007-03-09 03:25:35 · answer #2 · answered by doug_donaghue 7 · 0 0

Are you serious? f '=sin(x)+xcos(x)

f'' = cos x + [cosx - x sin x]
f''' = - 2 sin x - [ sin x + x cos x]
f'''' = - 3 cos x - [ cosx - x sin x]
f''''' = 4 sin x - [ sin x - x cos x]

do you see the pattern?

2007-03-09 03:31:34 · answer #3 · answered by piri82 3 · 0 0

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