the problem is as follows:
If a# b = a+ b+ b and b = a + a - b, how much greater is 6#4 then 6*4.
Thank you!
2007-03-09 03:02:59 · 3 answers · asked by danicecraney@sbcglobal.net 2 in Education & Reference ➔ Homework Help
I assume you messed up the question, and that it should read
a#b = a+b+b
a*b = a+a-b
Substitute the numbers into the function. Order is important.
6#4 = 6+4+4... How much is 6+4+4?
6*4 = 6+6-4... How much is 6+6-4?
The rest is simple.
2007-03-09 03:13:58 · answer #1 · answered by Anonymous · 2⤊ 0⤋
Okay, here is how you do it:
If, a#b=a+b+b
then, 6#4=6+4+4
6#4=14
6*4=24, so you can say that 14 is -10 greater than 24 or 6#4 is -10 more than 6*4
Or, if you made a typo and the second part is supposed to be a*b=a+a-b it would be
6*4=6+6-4
6*4=8
So 14 is 6 greater than 8, so 6#4 is 6 greater than 6*4
2007-03-09 03:14:37 · answer #2 · answered by emp04 5 · 0⤊ 2⤋
To start lets substitute b = a + a - b into a#b
a#b = a + (a + a - b) + b ---> b's cancel and b is irrelevant
a#b = 3a
6#4 = 3 * 6 = 18
6*4 = 24
Weird problem. It seems oddly defined.
2007-03-09 03:15:56 · answer #3 · answered by Will 4 · 0⤊ 0⤋