2007-03-09 02:42:55 · 19 answers · asked by lion of judah 5 in Sports ➔ Football ➔ UEFA Champions League
No he can't. The rules state that once you have played for one club in CL in that season you are disqualified for competing with a second in the same competition year. So 07-08 is when he will be eligible to play for Milan In CL.
2007-03-09 07:44:04 · answer #1 · answered by Anonymous · 2⤊ 1⤋
no since he already played for real in the champions this season. it doesn't matter that real are out of the competition. he will have to wait til next champions league to play for milan.
2007-03-09 11:35:04 · answer #2 · answered by mrkramer5 4 · 0⤊ 1⤋
No Because Steven Pressley and Paul Hartley both played in the qualifying round for Hearts who were knocked out and they were`nt able t play for Celtic after they signed in january
2007-03-09 14:21:51 · answer #3 · answered by jonnybeanos 2 · 0⤊ 1⤋
I'm afraid not.
Having assumed the position for Real he rendered himself ineligible to play for another club in the competition.
You may be interested to learn that I too am ineligible to play having not been registered with UEFA in good time
2007-03-16 15:16:59 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Not if he has played for Real all ready in the cup this season.
2007-03-09 10:52:37 · answer #5 · answered by richard_beckham2001 7 · 1⤊ 0⤋
No he is still cup tied cant play until next season
2007-03-09 10:46:51 · answer #6 · answered by Anonymous · 0⤊ 0⤋
nope he is cup tied cos he played for real in the match against lyon
have a nice weekend
2007-03-09 10:52:29 · answer #7 · answered by Frihah Anti-Milanist 4lyf! 6 · 0⤊ 1⤋
nope once he has played for one team in that competition he cannot play until the next season
2007-03-09 10:46:34 · answer #8 · answered by Anonymous · 0⤊ 0⤋
Nope!
2007-03-17 08:36:39 · answer #9 · answered by Dizzy Bizzle 2 · 0⤊ 0⤋
i think no .even now that real is out he is not going to play because he had played for real before.stupid rules.i would like him to play
2007-03-09 11:13:51 · answer #10 · answered by Anonymous · 0⤊ 1⤋