given sinx =- [sqrt (2)] /2 and that cos x is negative , find the other functions of x and the value of x?

Answer 1

No, do your own homework

Answer 2

Sin x is negative & cosx is also negative so x lies in the third quadrant sinx=1/sqrt2 x=45, tanx=1

Answer 3

cosx and sinx are -ve,hence,
they lie in the 3rd quadrant

we have a triangle
1,1,sqrt2 in the third
quadrant
sinx= -1/sqrt2
cosx= -1/sqrt2
tanx= (-1)/(-1)=1

hence x=180+45
=225 degrees or (5pi/4)
{0
i hope that this helps

Answer 4

x=2kp+45 p= 180!
cos(2kp+45)= -cos 45= -sqrt(2)/2
tanx=sinx/cosx= 1
cotx=cosx/sinx= 1

Answer 5

From (sin x)^2 + (cos x)^2 and the negativity of cos x
we get that

cos x = -sqrt (1-0.5) = - sqrt(2)/2 = sin x

sin2x = 2sinx cos x = 2*[sqrt(2)/2)]^2 = 1

We get that 2x = pi/2 + 2n*pi for any integer n

x = pi/4 + n*pi

Let us check cos x wfor n in {0,1}

cos (pi/4) > 0

cos (pi/4 + pi) = - cos (pi / 4) = - sqrt(2)/2
sin (pi/4 + pi) = -sin(pi/4) = -sqrt(2)


tan x = (sin x)/(cos x) = 1