A line perpendicular to the line that passes through the points (3, 4) and (5, 2)
1.)7/3
2.)2/3
3.)9/3
4.)4/3
2007-03-09 01:57:03 · 6 answers · asked by skate_freely 1 in Science & Mathematics ➔ Mathematics
find the slope of (3,4) and (5,2)
by the formula x2-x1 / y2-y1
then find it's recipricol.
2007-03-09 02:00:12 · answer #1 · answered by Anonymous · 0⤊ 0⤋
1
2007-03-09 10:12:19 · answer #2 · answered by yogesh gulhania 2 · 0⤊ 0⤋
A line passing through the points (x1,y1) and (x2,y2) has a slope of (y2-y1)/(x2-x1). This is simply the "rise over run" of the two points. For the points (3,4) and (5,2) the slope would be (2 - 4)/(5 - 3) = -2/2 = -1.
A line perpendicular to that line would have a slope that is the negative reciprocal or, in this case, +1
None of the choices you provide is correct. Did you copy the problem properly?
2007-03-09 10:08:50 · answer #3 · answered by dogsafire 7 · 0⤊ 0⤋
The line that passes through those points has a slope
m = (y2 - y1)/(x2 - x1) = (2 - 4) / (5 - 3) = -1
A line perpendicular to this one would have slope -1/m . In this case it would be 1, but that's not an option, so you must have wrote something wrong.
2007-03-09 10:05:29 · answer #4 · answered by javier S 3 · 0⤊ 0⤋
m = (y1-y2)/(x1-x2)
m = (4-2)/(3-5) = 2/-2 = -1
line perp = neg recip or 1
2007-03-09 10:08:51 · answer #5 · answered by Jack 2 · 0⤊ 0⤋
It is (x1-x2)/(y2 - y1) = (3 - 5)/(2 - 4) = 1
2007-03-09 10:07:16 · answer #6 · answered by Amit Y 5 · 0⤊ 0⤋