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A solution is prepared by adding 0.085 mol of K3[Fe(CN)6] to 0.52 L of 2.0 M NaCN. Assuming no volume change, calculate the concentrations of Fe(CN)63- and Fe3+ in this solution. The K (overall) for the formation of Fe(CN)63- is 1 1042.

2007-03-09 01:46:38 · 1 answers · asked by FaceFullofFashion 6 in Science & Mathematics Chemistry

1 answers

http://www.chemistry.com

2007-03-09 01:52:30 · answer #1 · answered by sunflare63 7 · 0 0

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