how do i solve this question?
2007-03-09 01:42:01 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
First of all, you have to consider the molecular weight (MW) of your compound. There are websites that can help you with this, and also the periodic table.
In your case, CO2 has a MW of 12+(2x16)= 44 g/mole
therefore 58.8 grams contain 58.8/44 = 1.336 moles
Simple, isn´t it?
2007-03-09 01:47:52 · answer #1 · answered by Jesus is my Savior 7 · 1⤊ 0⤋
CO2
C = 12 gm /mole
O = 15.9994 aprox = 16 gm /mole
CO2 = 12 + 16Ã 2= 44 gm /mole
Therefore 58.8 gm = 58.8 / 44 moles = 1.3364 moles
2007-03-09 09:53:26 · answer #2 · answered by Pranil 7 · 0⤊ 0⤋
CO2-Mr = 12+2(16)
=44g
44g=1mol
58.8g=1/44 *58.
=1.3364mol
or 1.3mol
2007-03-09 09:50:14 · answer #3 · answered by lUnJ@ 3 · 0⤊ 0⤋
You must be knowing that no. of mole of any substance is given by ,
n = m/M , where m=actual mass of substance taken , & M=molar mass of that substance .
In your example M=12+2*16=44.
m=58.8
threfore , n = m/M = 58.8/44 = 1.3364
2007-03-09 09:49:56 · answer #4 · answered by PINU 1 · 0⤊ 0⤋
http://www.chemistry.com
2007-03-09 09:51:43 · answer #5 · answered by sunflare63 7 · 0⤊ 2⤋
58.8g * 1mol = 1.34M
-------
44g
C =12
O=16
2007-03-09 09:46:43 · answer #6 · answered by DizziDazi 4 · 0⤊ 2⤋