A 0.5 kg stone is moving in a circular path attached to a string that is 75 cm long. The stone is moving around the path at a constant freq 0f 1.5 rev/sec. At the moment the stone is overhead, the stone is released. The velocity of the stone when it leaves the circular path is???
please help me. thanks!!
2007-03-09 01:41:50 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The circumference of the circle is 150pi, and the stone travels this path 1.5 times in one second, so the stone is traveling at 225pi cm/sec when it is released. In meters/sec this is approx. 7.06.
2007-03-09 02:31:46 · answer #1 · answered by sythyril 2 · 0⤊ 0⤋
the circumference of the circle that the stone is moving in is 2*pi*radius = pi*150 cm. the stone travels this distance in 1.5 seconds so its' velocity at the point of release is (pi*150)/1.5 cm/sec = 100 cm/second. the weight of the stone and the point of release do not matter
2007-03-09 10:02:18 · answer #2 · answered by michaell 6 · 0⤊ 0⤋