Algebra two questions?

Question

9: Solve and write in interval notation: | 2 - x | < -4
(-∞, -2) U (6, ∞)
No Solution
(-2, 6)
(-∞, ∞)


10: Solve and write in interval notation: | 3x + 4 | > -7
No Solution
(-∞, -11/3) U (1, ∞)
(-∞, ∞)
(-11/3, 1)


11: Solve and write in interval notation: | 4 - 2x | < 6
(-∞, -5) U (1, ∞)
(-∞, -1) U (5, ∞)
(-5, 1)
(-1, 5)


12: Solve and write in interval notation: | x/3 + 1/4 | > 1/2
(-9/4, 3/4)
(-∞, -9/4) U (3/4, ∞)
(-∞, ∞)
No Solution

Answer 1

9. B, No solution, anything with absolute value will be positive.
10. D, (-11/3, 1)
11. B, (-∞, -1) U (5, ∞)
12. A, (-9/4, 3/4)

Answer 2

9: Solve and write in interval notation: | 2 - x | < -4
No Solution

10: Solve and write in interval notation: | 3x + 4 | > -7
(-∞, ∞)

11: Solve and write in interval notation: | 4 - 2x | < 6
(-1, 5)

12: Solve and write in interval notation: | x/3 + 1/4 | > 1/2
(-∞, -9/4) U (3/4, ∞)

Answer 3

No Solution

(-∞, ∞)

(-1, 5)

(-∞, -9/4) U (3/4, ∞)

Answer 4

I'll show you how to do the first one, the other's are variations on this theme.

|2-x|<-4

taking the absolute value sign away requires that we "sandwitch" the RHS by changing it's sign and putting it on the LHS like so

4<2-x<-4

Now, take and subtract two from both sides

2<-x<-6

now divide through by -1, be careful, dividing by -1 or any negative coefficient requires you flip the inequality signs around like so

-2>x>6
so the answer is (-2,6)

Answer 5

Do the math, that is 4 questions.

Answer 6

enfinty thats no more