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what's a dipolar bond? and how does it effect the solubility and the melting point?
please give me a clear explanation. thanks alot!

2007-03-09 00:48:44 · 3 answers · asked by Aaron A 3 in Science & Mathematics Chemistry

3 answers

Amino-acid is the type of polar compound;

A polar compound has a part of its molecule bearing a positive charge and an other part a negative charge of the same absolute value; this is called a dipole meaning 2 poles. These compounds are highly soluble in water which is a polar solvent. Water is a dipole with a negative charge on oxygen and a positive charge in the middle of the line joining the two hydrogen's. Solvent dipolar dissolve solvent compound easily due to electric attraction;

2007-03-09 01:01:20 · answer #1 · answered by maussy 7 · 0 0

Amino Acid Solubility In Water

2016-11-01 08:33:04 · answer #2 · answered by ? 4 · 0 0

A compound is comprised of one or more chemical bonds between atoms. The polarity of each bond within the compound determines the overall polarity of the compound: how polar or non-polar it is. A polar molecule usually contains polar bonds - bonds which have unequal sharing of electrons between the two atoms involved in bonding. A non-polar compound usually contains non-polar bonds - bonds which have identical or similar sharing of electrons.

Besides bond polarity, the other factor that decides if a molecule is polar is the molecule's symmetry. Even if a compound contains only polar bonds, it may be non-polar overall as the direction of the polarities cancel each other out, giving the molecule a net polarity of zero. This occurs in boron trifluoride, which contains three identical polar bonds all canceling each other out due to their symmetrical arrangement.

Examples of household polar molecules include ammonia and sugar (glucose). Polar molecules are generally able to dissolve in water (hydrophilic) due to the polar nature of water - like dissolves like. Polar molecules have slightly positive and slightly negatively charged ends

2007-03-09 01:00:34 · answer #3 · answered by Anonymous · 0 0

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