2007-03-09 00:28:23 · 12 answers · asked by manoj m 1 in Science & Mathematics ➔ Other - Science
measure the candle and mark off the half way point; i.e. if the candle is 8 inches long, make a mark at 4 inches. When the candle burns down to the mark, light the 2nd candle. When the 2nd candle burns out it will be 1 and a half hours.
2007-03-09 00:32:33 · answer #1 · answered by canela 5 · 0⤊ 1⤋
Place the 2 candles next to each other and light one-- when it reaches 1/2 the height of the other one, you know 30 mins has gone by-- light the other candle (it will burn for 1 full hr) and that will equal 1 hr and 30 mins. That way you don't have to measure anything.
BTW, some ppl have suggest burning the first candle completely and then lighting the second one- you can't burn the first one completely, b/c you won't know when the second candle has burned 1/2 way...
2007-03-09 00:37:29 · answer #2 · answered by Bio Instructor 4 · 0⤊ 2⤋
First measure the length of each candle. Mark half of candle.
Light first candle after exhausting this will measure 1 hour.
Now light second candle & let it burn up to half of it. will measure required next half hour.
2007-03-09 00:35:42 · answer #3 · answered by Pranil 7 · 0⤊ 0⤋
Thank you for question for brain.
All questions now a days are based on knowledge like KBC.
Use 1 candle. When it is half, use 2nd candle. 2nd will end after a total time of 90 minutes.
How can I get more questions for use of brain? I am at 98105 38183
You can write to: Four Square monthly, Moti Nagar 110015
2007-03-09 00:42:35 · answer #4 · answered by Anonymous · 0⤊ 0⤋
may be you want the answer by given the condition that we dont have any measuring device(not even scale).
do one thing..
first burn the first candle
which will end up in an hour
now
burn the second candle from both the sides..which will directly burn in half an hour
so the total time is 1.30 hrs
2007-03-12 23:24:15 · answer #5 · answered by Anonymous · 0⤊ 0⤋
permit h be the peak of the candle velocity of First Candle = h/4 velocity of 2nd Candle = h/3 how many hours after being lit replaced into the 1st candle two times the peak of the 2nd? permit r be the peak of the 2nd candle at that element (t). r = h - (h/3)t on an identical time(t), the peak of the 1st candle could be 2r 2r = h - (h/4)t 2(h-(h/3)t) = h - (h/4)t 2h - (2/3)ht = h - (a million/4)ht 2-(2/3)t = a million - (a million/4)t t(2/3-a million/4) = a million t = 12/5 hr or 2.4 hr
2016-10-17 22:54:59 · answer #6 · answered by Anonymous · 0⤊ 0⤋
Simple - burn 1 candle until it's gone. That's one hour.
Then light both ends of the other candle. It'll burn twice as fast, and be gone in 30 minutes.
Be sure to tell your teacher that you got the answer from the internet.
2007-03-09 00:31:51 · answer #7 · answered by Ralfcoder 7 · 3⤊ 1⤋
1st make tha whole candle burn and then after that lit the candle from both the sides...the time measured willl be 1.5 hr...
2007-03-09 01:18:18 · answer #8 · answered by rohgat 1 · 0⤊ 0⤋
First candle cut it two light it both at once and then after that light second one and both will burnt out within 1.30hrs.
2007-03-09 00:51:04 · answer #9 · answered by Spartan Total Warrior 5 · 1⤊ 0⤋
Burn one candle until it's gone, then burn the 2'nd one. When it's half burned, it's 1:30.
HTH ☺
Doug
2007-03-09 00:33:39 · answer #10 · answered by doug_donaghue 7 · 0⤊ 1⤋