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...in a household in place of a standard 60 W bulb over the course of one week, where each bulb would be on 10% of the total hours of the week? What would the total savings to consumers be in the US, assuming all of 50 million households in teh US try this with one bulb each? Assume a utility rate of $0.10 per KWh.

2007-03-08 05:46:13 · 2 answers · asked by sk_whit 1 in Science & Mathematics Engineering

2 answers

0.002 cents per hour per light

2007-03-08 05:53:00 · answer #1 · answered by uisignorant 6 · 0 0

This sounds like somebody wanting me to do their homework for them.

The savings would be 20 watts for the time it is used
There are 168 hours in a week so 10% of that is 16.8 hours.
Power companies charge by the kilowatt/hour so are paying 0.0168 kwatt hours, which at your assumed cost of 0.1 per kwatt hours that would be a total cost of $0.00168.

Now if you multiplied that cost by the 50 million households then you would get you a savings of $84,000 per week. Which isn't that bad, with 52 weeks in a year comes to a total savings of $4,368,000 and $4 million a year is nothing to sneeze at. Then when you consider the reduction in the power demand and the resulting pollution created by that demand it starts to look like a good idea. Of course I figured that out years ago and the only lamp I have that doesn't use a fluorescent bulb is my torch lamp.

Additional Note: It was pointed out ot me that I only calculated for 1 watt so the final answer is a savings of $1,680,000 per week and a savings of $87,360,000 per year making it a better deal than I thought it would be.

Thank-you floodtl (grumble, grumble you caught me in a rare mistake).

2007-03-08 13:59:05 · answer #2 · answered by Dan S 7 · 0 0

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