Hey,
What does it mean when the force is fully reversed?! Will the force/torque applied on the bike pedal/crank considered fully reversed?! I know it is, but I don't know why. In my analysis, I used weight of the rider as the only force applied to the pedal as it rotates, and that force is fully reversed to calculate factors of safety in the pedal/crank-arm.
How would I explain the logic behind that in the report?! Any ideas?
Thanks!
2007-03-08 05:24:36 · 3 answers · asked by abe_cooldude 1 in Science & Mathematics ➔ Engineering
I'm speculating like crazy 'cause I don't really know your situation, but here are some thoughts to kick around.
Assuming, a one-way clutch is not between the wheel and its sprocket, wouldn't the bicycle's inertia back-drive the pedals and create a reversed force against the rider's foot?
Often, in physics problems the sign of a force vector is changed. This corresponds to a 180 degree reversal of the direction of the force. In other words, you can change the sign of the magnitude of a vector or you can reverse the direction of the vector. Either action accomplishes the same result.
Recall that the weight of the rider could be applied equally to both pedals with no net effect. If the wheel is allowed to back-drive the pedal cranks, wouldn't the force on the rider's rear foot then be negative?
I'm not sure I've been much help. Hopefully my "food for thought" suggestions will provide new directions for your consideration. Good Luck.............
2007-03-08 05:54:26 · answer #1 · answered by Diogenes 7 · 0⤊ 0⤋
It just what it sounds like - fully reversed, from positive force/moment, to the negative vector of the same force/moment. If you take your pencil and try to break it in the down direction, the fully reversed stress would be trying to break it in the up direction. (and not just releasing the force.)
I don't think a pedal/crank would be fully reversed. You push down on it with force...but when it goes to its up position, you're not really pulling up on it in the opposite direction - its just unstressed at that point.
2007-03-08 05:38:05 · answer #2 · answered by trader_dude_turned_surfer 3 · 0⤊ 0⤋
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2014-12-08 14:43:51 · answer #3 · answered by Anonymous · 0⤊ 0⤋