How do I calculate the weight of a steel bar per square foot?

Question

I have a bar:

Width: 2'
Height: 1'
Thickness: 0.100'

How do I calculate the weight per square foot?

Answer 1

Volume of a steel bar
=Width *Height*Thickness
=2*1*0.1 ft^3
=0.2 ft^3
0.2 cubic foot = 0.005 663 369 cubic meter
mass/volume=density
mass=Density*volume
mass=7850 kg/m^3* 0.005 663 369 m^3
mass=44.46 kg.

Total Area
=2*1
=2 ft^2
Total weight
=44.46 kg
weight/sq. ft
=44.46/2
=22.23 kg.

Answer 2

multiply the width by the height to get the area in square feet. Weigh the bar and divide by the area. This will give you pounds per square foot.

Answer 3

measure the total weight and divide by the volume in cubic feet and you will get the density in kg/ft³ Note that this is a very unusual mixture of units. Or you can look up the density in kg/m³ and convert to kg/ft³

Answer 4

Steel weighs 0.284 pounds per cubic inch (490.75 lbs/cu ft.)
Weight = 24 x 12 x 1.2 x 0.284 = 98.15 lbs

Or we could do:

2 x 1 x 0.100 x 490.75 = 98.15 lbs

Answer 5

Average density of steel (lb/in3) = 0.283

For your bar:
Volume = H * W * T = (2*12) * (1*12) * (0.10*12) = 345.6 in3

Therefore weight of bar = (Volume) * (Density) = 97.805 lb

Depending on the edge area, you'd then have:
(Laying on 2x1 surface)
Wt/ft2 = 97.805 / (2*1) = 48.902 lb/ft2
(Laying on 2x0.1 surface)
Wt/ft2 = 97.805 / (2*0.1) = 489.025 lb/ft2
(Laying on 1x0.1 surface)
Wt/ft2 = 97.805 / (1*0.1) = 978.050 lb/ft2