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I have made a bridge rectifier using a transformer of specification 12V 6A, and in the bridge I have used 1A diode, My question is that why does not the diode explodes and what is the power I am getting at the output.

2007-03-07 17:46:15 · 4 answers · asked by Kasprov 1 in Science & Mathematics Engineering

I have made a bridge rectifier using a transformer of specification 12V 6A, and in the bridge I have used 1A diode, My question is that why does not the diode explodes and what is the power I am getting at the output. capacitor is 1000uf 16v.

2007-03-07 18:32:03 · update #1

4 answers

The numbers you give are the max ratings of the parts, but when used in a circuit, it is the actual current drawn that matters. What you have left out is the load on the rectifier output. If the circuit is unloaded, no current is drawn, and that is much less than 1A or 6A, so neither part will burn out. However, if you load the circuit and draw current through the diodes and transformer, you can reach a point when 1A is being drawn through the diode, and they will burn out. The diodes will fail before the transformer. A full wave bridge rectifier with 12VAC input and silicon diodes will produced an output voltage of 12*√2-1.4=15.6V peak. The diodes will exceed their rated capacity if the load is less than 15.6 ohms

You can draw a theoretical maximum of 15.6 watts from the circuit (the transformer, rated at 6A, will not drop significantly at 1A), but you can get that only with a well-filtered output. The actual power capacity is a complicated calculation, depending on the filter capacitor and the peak surge current capacity of the diodes.

2007-03-07 17:55:29 · answer #1 · answered by gp4rts 7 · 1 0

Because you have no load. So you have a transformer connected to some diodes.....what's drawing current? Nothing from what you described. You have just rectified AC to a DC ripple. There's nothing pulling 6A, just because that's the rating of your transformer. Now if you connect a load which draws 6A, then watch the diode explode.

2007-03-08 13:28:43 · answer #2 · answered by joshnya68 4 · 0 0

You should tell us the load conditions of the circuit. A very important parameter would be the load resistance and the other important factor to consider would be if your load is highly inductive or not.

Drop me an email and I will send you an example of the calculations I use for power supplies.

2007-03-08 03:03:11 · answer #3 · answered by Soutballas 1 · 0 0

it doesnot explode becoz it has no like poles

2007-03-08 01:54:09 · answer #4 · answered by PRASSANA K 3 · 0 1

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