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now i have to do insulation on that whole container to reduce the heat, I have to cover length,width and height as well. So, please can anyone say how much quantity of insulation do i required. and how to calculate this whole procedure in Sq ft OR Sq mtr.

2007-03-07 15:15:42 · 2 answers · asked by iemmustafa 1 in Science & Mathematics Engineering

2 answers

the faces' dimensions to be covered are :
18' x 11'
18' x 8'
and 11' x 8' each of which there are 2.

thus the total surface area will be :
2*(198) + 2*(144) + 2* (88) sq. ft.
which totals to 396+288+176
=860 sq ft.
now each ft = 12* 2.54 = 30.48 cm.
thus each sq. ft. is 30.48 ^2 sq. cm or .3048^2 sq.m
i.e.929.0304 sq. cm. or .09290304 sq. m.
multiplying this with the sq. ft answer will give you the required area to be insulated...

2007-03-07 15:26:05 · answer #1 · answered by s_d_sondhi 2 · 0 0

Without knowing what R factor you require, one can only generalize. Let t be insulation thickness (expressed in ft)
V = (18 + 2t) (11 + 2t) (8 + 2t) - (18)(11)(8)
V = (18 + 2t) (88 + 38t + 4t^2) - 1584
V = 1584 + 176t + 684t + 76t^2 + 72t^2 + 8t^3 - 1584
V = 860t + 148t^2 + 8t^3
t . V(ft^3)
1" 72.7
2" 147.5
3" 224.4
4" 303.4
5" 384.6
6" 468
7" 553.6
8" 641.5
9" 731.6
10" 824.1
11" 918.9
12" 1,016

Square footage of slab insulation required will be
S = 2(18 + 2t)(11 + t + 8 + t) + 8*11
S = 2[(18 + 2t)(19 + 2t) + 8*11]
S = 2[(18(19 + 2t) + 2t(19 + 2t) + 8*11]
S = 2[342 + 36t + 38t + 4t^2 + 88]
S = 860 + 148t + 8t^2
Again, t needs to be expressed in ft.
Note that 860 ft^2 is the surface area of the original container.

2007-03-07 16:02:06 · answer #2 · answered by Helmut 7 · 0 0

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