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6 answers

you are clearly buying a volume of gasoline (gallons) and therefore a mass of gasoline.

Since, according to Einstein and his famous E=mc^2, energy is equivalent to mass, you are in fact buying energy too.

The energy you get burning gasoline, however, is due to chemical reactions taking place, rather than any apparent conversion of mass to energy.

2007-03-07 14:39:18 · answer #1 · answered by Dr W 7 · 1 0

No. The conversion of energy equation refers to mass that is lost as a result of a nuclear reaction, and not to energy caused by chemical reaction (such as combustion of gas)

2007-03-07 22:26:42 · answer #2 · answered by cattbarf 7 · 0 0

We don't buy energy at the pump. We buy a volatile mixture that is easily converted into potential energy.

2007-03-07 22:25:44 · answer #3 · answered by ttpawpaw 7 · 0 1

no,E=mc^2 is only applicable for energy coming from nucleus of an atom,like nuclear power plants

2007-03-07 22:29:22 · answer #4 · answered by aldrin m 2 · 0 0

you don't buy energy at the pumps. you buy fuel the engine converts it into energy.
fuel=m
engine=c
power to the wheels=^2

2007-03-07 22:27:17 · answer #5 · answered by geezerrex 5 · 0 1

No. You are buying increasingly more expensive, but decreasingly less powerful gasoline. It is being made even less powerful by the forced addition of alcohol, now days, no thanks to environ-mental tards.

2007-03-07 22:40:20 · answer #6 · answered by Anonymous · 0 1

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