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building a circular structure with 8x8x16 concrete blocks using a 34 ft inside diameter x 10 feet in height. how many blocks would i need? consider this a structure with out doors or window openings.

2007-03-07 00:56:37 · 3 answers · asked by thedude50 1 in Science & Mathematics Engineering

3 answers

34ft x pi = 106.81ft ID, which is 1282 inches. Divided by 16 is 80.11 blocks. 10ft = 120 inches, divided by 8 inches is 15 blocks high, times 80 = 1200 blocks total.

But allowing for mortar gap of slightly more than 1/2 inch between levels, you'd only need 14 blocks to reach a 10-ft height, so total would be 14 x 80 = 1120 blocks total. And going around with about the same mortar gap would be 78 instead of 80 blocks, so 78 x 14 = 1092 blocks, assuming approximately 1/2" mortar gaps horizontally and vertically.

2007-03-07 01:28:16 · answer #1 · answered by Gary H 6 · 0 0

approx. 510 they come 90 to a cube. id order a few extra...ooops i was
figuring
wrong...
sorry

2007-03-07 01:05:09 · answer #2 · answered by Anonymous · 0 0

Are those metric or standard cement blocks?

2007-03-07 00:59:23 · answer #3 · answered by Anonymous · 0 0

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