Too bad she failed at suicide.
2007-03-06 06:13:25 · 10 answers · asked by Anonymous in Society & Culture ➔ Religion & Spirituality
This young woman is mentally unstable and she needs someone who loves her very much right now. She is not coping with life and no one seems to be of help to her. I have never seen anyone that needs Jesus Christ more than her. Only Jesus can turn her life around to change the evil to good.
You will answer for every evil word you speak. Please be more careful with your casual conversation about people. She needs our prayers and our love and not criticism. Let's pray for her instead.
2007-03-06 06:22:32 · answer #1 · answered by Jeancommunicates 7 · 0⤊ 2⤋
The anti-christ is predicted in the bible to be a man unknown but just randomly appears in the world.. from Europe. If the antichrist came,... then all the believers wouldnt be here.. so i wouldnt be able to answer ur question right now
2007-03-06 06:29:08 · answer #2 · answered by Rachel H 1 · 0⤊ 0⤋
No, Johnny Rotten is the antichrist.
2007-03-06 06:17:57 · answer #3 · answered by Anonymous · 0⤊ 1⤋
No. Brittany is not important enough to be the Antichrist... I wouldn't even let her mop my office.
2007-03-06 06:17:22 · answer #4 · answered by billthakat 6 · 2⤊ 1⤋
She couldn't be the anti-Christ. The anti-Christ would be much older...and a guy. She is just someone that is in desperate need of....someone like...well...me.
2007-03-06 17:37:11 · answer #5 · answered by gotherunereadings 3 · 0⤊ 0⤋
maybe we should give her a break and pick on someone
better able to defend themselves. She has enough struggles of her own without our two cents
2007-03-06 06:17:46 · answer #6 · answered by ? 5 · 1⤊ 1⤋
Nope, just lost and in need of help.
2007-03-06 06:24:59 · answer #7 · answered by Jouvert 5 · 0⤊ 0⤋
yes
2007-03-06 06:16:46 · answer #8 · answered by Anonymous · 0⤊ 2⤋
I thought it was Mick Jagger???
2007-03-06 06:22:02 · answer #9 · answered by Anonymous · 1⤊ 0⤋
yes she is
and also mad
2007-03-06 06:18:01 · answer #10 · answered by I am an Indian 4 · 0⤊ 1⤋