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2007-03-05 07:50:07 · 7 answers · asked by purplewolf 1 in Science & Mathematics Engineering

the pontoon is 3.05m wide, 5.9m long, 1.2m heigh and has a draught of 0.7m

2007-03-05 08:04:25 · update #1

7 answers

the maximum load cannot be determined by the information you have submitted.

here you go.

Bouyancy-(volume displacement of pontoon x weight of water for that volume)-weight of pontoon materiel

if you are just looking for the amount of weight than can be added before it is underwater use that

2007-03-05 09:09:35 · answer #1 · answered by BMS 4 · 0 0

Find the volume of the pontoonthat is underwater JUST as the pontoon is about to sink and that mass in water minus the mass of the boat is the boat's maximum load.

2007-03-05 08:56:33 · answer #2 · answered by Scooter_MacGyver 3 · 0 0

Its the evenly distributed weight that will increase the draught to 1.5 meters. (just before it sinks)
Volume of pontoon ( approximately) = 3.05*5.9* 1.5=21.6m^3
Volume below water = 3.05 *5.9*0.7 =12.6m^3
So volume of pontoon above water level =21.6 - 12.6 =9m3
1kg water = 1000cc^3 =1 Litre
So 1m^3 water = 1000kg =1metric ton =2200 lbs

9m^3 = 9000kg = 9 metric tons

which is approximately 9 British tons
Imperial measurement 2240lbs = 1ton
So your pontoon would sink as it would have 360 lbs overweight.

2007-03-05 09:12:53 · answer #3 · answered by mad_jim 3 · 0 0

3.05 x5.9 x1.2 =21.594

this hasnt taken the wait of the pontoon in to consideration

the pontoon will float 21594 kgs

if its in the water & you only have .5 above the water line

3.05 x 5.9 x .5 = 8997 Kgs

2007-03-05 08:58:47 · answer #4 · answered by Anonymous · 0 0

A pontoon normally has a max load printed on it.

2007-03-05 07:53:46 · answer #5 · answered by R.E.M.E. 5 · 0 0

Surely it will depend on the size of the pontoon.

2007-03-05 07:58:52 · answer #6 · answered by Anonymous · 0 0

You need more info. exact type of steel and any tempering How is the bracket supported and exactly where is the load attached. What are the angles? .

2016-03-29 01:04:40 · answer #7 · answered by Anonymous · 0 0

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