No other combition.
[It's something like C=xF+y, a linear equation in other words. And we know that 0°C=32°F (freezing), and 100°C=212°F (boiling). That should be enough to find x and y:
0 = 32x+y
100 = 212x+y]
[Compare with y=m*x+c,where m=slope=5/9 which is constant,c=constant=32, so no other combination will give you the both sides equal.]
C=5/9*[F-32]
[F-32]=C*9/5
F=[C*9/5]+32
[-40*9/5+32]C
= [-72+32] C
= -40 C
http://en.wikipedia.org/wiki/Degree_Fahrenheit
2007-03-03 06:32:13
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answer #1
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answered by Anonymous
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To be technically correct you should call it -40FC.
The FC scale is not known to many people outside of Canada. There are actually a great many temperatures during the winter which are all about the same in FC. When asked what the temperature is, a simple response of "it is FC or F#$&ing Cold" is an accurate enough description.
2007-03-03 13:11:15
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answer #2
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answered by Anonymous
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none else,
because the relation among the two units (°C/°F) is a LINE:
°F=°C*9/5+32
same as in
y=ax+b
and TWO LINES only cross in a single point,
in our case it's P(-40°C,-40°F)
2007-03-03 13:21:48
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answer #3
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answered by Mario Roma 2
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this is the formula:
°C x 9/5 + 32 = °F
I think those are the only numbers that are the same,
2007-03-03 13:16:48
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answer #4
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answered by Jason S 2
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none.
Think of it this way. You want to solve the SIMULTANEOUS EQUATIONS
y = x, and y = (x-32)*(5/9). The latter is the conversion from Fahrenheit (x) to Celsius (y).
There is only one solution to this system of equations.
2007-03-03 13:07:18
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answer #5
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answered by portiaeliot1966 2
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That's it, at -40. There are no other equality points.
2007-03-03 13:08:55
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answer #6
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answered by J 5
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-30
2007-03-03 13:08:17
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answer #7
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answered by tom2day 2
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I believe that is the only one
2007-03-03 13:08:01
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answer #8
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answered by tomkat1528 5
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