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then the night manager comes and said the price of the room was wrong the room was really 25$ so the manager gives a employee a five to give to the guys. the employee thought they could not split 5$ so he put 2$ in his pocket. he gives the guys a dollar each. so instead of paying ten each they paid 9 and 9 times 3 is 27 pluse the two that the employee took wich only equals 29 dollars where did the other dollar go????????

2007-03-02 16:22:40 · 10 answers · asked by sarah 1 in Entertainment & Music Jokes & Riddles

10 answers

They're misleading you with incorrect (backwards) math.

3 men each gave 10 dollars: 3 x 10 = 30
$25 was for the room and the bellboy was given $5. The bellboy gave $1 back to each of the 3 men, and kept $2 for himself.
1×3+2=5, 5+25=30
There is no missing dollar.

2007-03-02 16:26:02 · answer #1 · answered by They call me ... Trixie. 7 · 2 1

The facts in this riddle are clear: There is an initial $30 charge. It should have been $25, so $5 must be returned and accounted for. $3 is given to the 3 friends, $2 is kept by the bellhop - there you have the $5. The trick to this riddle is that the addition and subtraction are done at the wrong times to misdirect your thinking - and quite successfully for most. Each of the 3 friends did indeed pay $9, not $10, and as far as the friends are concerned, they paid $27 for the night. But we know that the clerk will tell us that they were charged only $25 and when you add the $3 returned with the $2 kept by the bellhop, you come up with $30.

From Ward, another way to look at this one: My answer:

The following night two friends check into the same motel. Once again the clerk charges them $30, or $15 per person. After the clerk remembers the total rate is only $25 he sends the bellhop upstairs with five $1 bills to pay the two friends back. The bellhop knows he got away with larceny once so he tries it again. But this time he pockets $3 and returns $2 to the hotel guests ($1 per guest). So each of the two guests got $1 back from their original $15. Therefore each paid $14 which is a total payment of $28 for the room. Now the bellhop has $3, the guests paid $28, for a total of $31....THERE'S THE MISSING DOLLAR!!!!

2007-03-02 18:35:47 · answer #2 · answered by ILLUSTRATOR 3 · 1 0

the original math is misleading. look at it this way:
The cost of the room is actually $27 because the employee kept $2 for himself. Each of them gets $1 back, which equals $3.

$30-$5 = $25 is what the hotel charged for the room
$25+$2 = $27 is what the men paid after the employee took the money
$27+$3 = $30 is the total after each man receives $1 back

2007-03-02 16:40:29 · answer #3 · answered by riffers21 4 · 0 0

It didn't go anywhere.

You have 3 people who paid $9, which = $27. The employee kept $2 and $27 - $2 = $25, which is what the motel takes.

The problem arises because you assume you are supposed to add the employee's $2 to the $27 and try to get $30. Instead, since the final price is $25, you are supposed to subtract the $2 from the $27 to get $25, which you do.

It's a trick question.

2007-03-02 16:38:28 · answer #4 · answered by Anonymous · 1 0

They paid $27 total ($9 x 3) of which $25 went to the hotel and $2 went to the employee. The other $3 was returned to them, making $30 total.

2007-03-02 16:50:11 · answer #5 · answered by Anonymous · 0 0

i used it to buy some crisps

you subtract the $2 from the $27, rather than adding it. then it equals $25 which is the cost of the room.
you made me think there!

2007-03-02 16:25:40 · answer #6 · answered by Anonymous · 2 0

i stole it...lol (jk) 25 was room fee, 3 back to the guys, 2 employee's tip

2007-03-02 16:28:54 · answer #7 · answered by Anonymous · 0 0

good one i need the anser asap theres 1 lost or 1 gained it gos to the tip or 4 tax????????????

2007-03-02 16:28:33 · answer #8 · answered by Anonymous · 0 0

I used it for candy.

2007-03-02 16:28:50 · answer #9 · answered by kenmauiphoto 5 · 0 0

stop confusing me.

2007-03-02 22:13:59 · answer #10 · answered by blubaby77 2 · 0 0

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